Question

One litre of bottle A with 8% sugar solution is mixed with an unknown
quantity of bottle B with 11% sugar solution such that the mixture has
10% sugar solution.
How many litres of sugar solution from bottle B
was mixed with bottleL

Answer 1

Answer:

2L of sugar solution was in bottle B.

Step-by-step explanation:

As per the data given in the question,

We have,

Sugar contents in bottle A = 8%

Mixture in bottle A = 1 L

Let the mixture in bottle B be $x$

So, according to questiom,

$8\%of1L +11\%of\:x = 10\%of(1L+x)\\80ml + 0.11x = 0.1(1L+x)\\0.11x-0.1x=0.1L-80ml\\0.01x= 20ml\\x= 2000ml = 2L$

Hence,

2L of sugar solution was in bottle B.

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Answer 2

Concept

Mixtures are created by mixing two solutions with different composition.

Given

One litre of bottle A with 8% sugar solution is mixed with an unknown

quantity of bottle B with 11% sugar solution.

Find

How many litres of sugar solution from bottle B was mixed with bottle A.

Solution

The sugar solution parts in first solution are 1000/8.

Let the quantity of Bottle B be x litres.

The sugar solution parts in second solution will be x*1000/11.

The sugar parts in the final mixture are (x+1)1000/10.

$\frac{1000}{8} +\frac{x*1000}{11} =\frac{(x+1)*1000}{10}$

$\frac{1}{8}+\frac{x}{11} =\frac{x+1}{10}$

(11+8x)10=88(x+1)

110+80x= 88x+88

8x=22

x=2.75 litres

Litres of sugar solution from bottle B was mixed with bottle A is 2.75 litres

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