Question

One litre of CO2 is passed through red hot coke. The volume becomes 1.4 litres at same temperature and pressure. The composition of products is

Answer 1

Chemical Equation:CO2 + C ----> 2CO

According to the problem, one litre of CO2 reacts with 1 mole of Carbon to produce 2litres of CO.
 Given 1.4L is the mixtures of gases[CO+unreacted CO2].

If X litres of CO2 are reacts to give 2X litres of CO .

Total volume of mixture will be=CO2+CO
VolumesV (mixture)=V(new volume of CO2) +V (CO)=1.4L
V(new CO2)=V(initial Volume CO2)-V(reacted CO2)=(1-x)L
V(CO)=2x
so , we get
V(new volume of CO2) +V (CO)=1.4L
(1-x)+2x=1.41-x=1.41-1.4=X
X=0.4L
From ,V(new CO2)=V(initial Volume CO2)-V(reacted CO2)=(1-x)L
=1-0.4=0.6 L of CO2
Since V(CO)=2x
Volume of CO=2x0.4=0.8L of CO

Therefore, the composition of product is 0.6 litres of CO2 and 0.8 litres of CO.

Answer 2

According to the problem, one litre of CO2 reacts with 1 mole of Carbon to produce 2litres of CO.

 Given 1.4L is the mixtures of gases[CO+unreacted CO2].

If X litres of CO2 are reacts to give 2X litres of CO .

Total volume of mixture will be=CO2+CO

VolumesV (mixture)=V(new volume of CO2) +V (CO)=1.4L

V(new CO2)=V(initial Volume CO2)-V(reacted CO2)=(1-x)L

V(CO)=2x

so , we get

V(new volume of CO2) +V (CO)=1.4L

(1-x)+2x=1.41-x=1.41-1.4=X

X=0.4L

From ,V(new CO2)=V(initial Volume CO2)-V(reacted CO2)=(1-x)L

=1-0.4=0.6 L of CO2

Since V(CO)=2x

Volume of CO=2x0.4=0.8L of CO

Therefore, the composition of product is 0.6 litres of CO2 and 0.8 litres of CO.