Chemistry, asked by lavanyarupasri0007, 8 months ago

One litre of mixture of CO
and CO2 is passed through
red hot charcoal in tube. The
new volume becomes 1.4
litre. Find out % composition
of original mixture by
volume. All measurements
are made at same P and T.​

Answers

Answered by XxMrNobodyxX
11

Answer:

One litre of mixture of CO

and CO2 is passed through

red hot charcoal in tube. The

new volume becomes 1.4

litre. Find out % composition

of original mixture by

volume. All measurements

are made at same P and T.

Answered by harshking1354
4

Explanation:

C+CO

2

→2CO

⇒ Initial volume =1L

Final volume =1.6L

Let V

CO

2

=x V

CO

=(1−x)

⇒(1−x)+2x=1.6

1+x=1.6

x=0.6

∴%CO

2

=60%, %CO=40%

Hence, solved.

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