One litre of water contains 10^-7 mole hydrogen
ions. The degree of ionization in water will be
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3
Answer:
α=18×10
−10
In percentage α=1.8×10
−7
%
Explanation:
H
2
O⇌H
+
+OH
−
C 0 0
C(1−α) Cα Cα
Cα=10
−7
[H2O] =
18
1000
= 55.55 M
C= 55.5M
So α=18×10
−10
In percentage α=1.8×10
−7
%
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