One litre solution is made by addition of 1 mole H2C2O4 and 1 mole of Na2C2O4. Calculate pH of the solution. (Pka1= 1.22 ,Pka2 = 4.2)
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Answer:
2 mole, equimolar mixture of Na
2
C
2
O
4
and H
2
C
2
O
4
required V
1
L of 0.1MKMnO
4
in acidic medium.
As the mixture is equimolar, 1 mole of each, Na
2
C
2
O
4
and H
2
C
2
O
4
are present.
∴eq. of Na
2
C
2
O
4
+eq. of H
2
C
2
O
4
=eq. of KMnO
4
(equivalent=mole×valencefactor}
⇒1×2+1×2=V
1
×0.1×5{∵ valence factor=Change in oxidation state per molecule}
⇒V
1
=8L
Case II:
2 mole, equimolar mixture of Na
2
C
2
O
4
and H
2
C
2
O
4
required V
2
L of 0.2MNaOH for neutralization.
eq. of Na
2
C
2
O
4
+eq. of H
2
C
2
O
4
=eq. of NaOH
⇒1×1+1×1=V
2
×0.2×1
⇒V
2
=10L
∴V
1
:V
2
=8:10=4:5.
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