One man and 2 boys can do a work in 5 days. Two men and 1 boy can do the work in 4 days. In how many days can 1 man and 1 boy complete the work?
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Answer:
Let M be the proportion of the job that one man can complete in one day, and let B be the proportion of the job that one boy can complete in one day. We know:
1M + 2B = 1/5
2M + 1B = 1/4
Let's subtract twice the first equation from the second:
1M + 2B = 1/5
4M + 2B = 1/2
------------——
-3M = -3/10
M = 1/10
So one man can do 1/10 of the job by himself per day.
1/10 + 2B = 1/5
2B = 1/10
B = 1/20
One boy can do 1/20 of the job by himself per day.
1 man + 1 boy can do 1/10 + 1/20 = 3/20 of the job in one day, so it would take them 20/3 (or 6 2/3) days.
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