Question

one man can do a piece of work in 3 hours;another can do the same piece of work in 2 hours. how long will they take if they work together?​

Answer 1

Answer:

Hey friend,

Here is the answer you are searching for,

$work \: done \: by \: 1st \: man \: in \: 1 \: hour \\ = \frac{1}{3} \\ work \: done \: by \: 2nd\: man \: in\: 1 \: hour \\ = \frac{1}{2} \\ net \: work \: done \: by \: both \: in \: 1 \: hour \\ = \frac{1}{2} + \frac{1}{3} \\ lcm \: of \: denominators = 6 \\ = > both \: 1 \: hour \: work \\ = \frac{1}{2} + \frac{1}{3} = \frac{3 + 2}{6} = \frac{5}{6} \\ > total \: time \: required \: by \: both \\ = \frac{6}{5} = 1\frac{1}{5} hour$

HOPE IT HELPS YOU.

PLEASE MARK AS BRAINLIEST...