one man had some mangoes out of them 1/25 were sold and 1/5 of the total mangoes turned out or spoiled it the remaining few clean mangoes 38 find the total number of mangoes
Answers
Step-by-step explanation:
Given:-
One man had some mangoes out of them 1/25 were sold and 1/5 of the total mangoes turned out or spoiled and the remaining few clean mangoes 38.
To find:-
find the total number of mangoes?
Solution:-
Let the total mangoes the man had be X
Number of mangoes are sold = 1/25th of total mangoes
= (1/25)×X
= X/25
Number of mangoes are turned out or spoiled
=1/5 of the total mangoes
=>(1/5)×X
=>X/5
Number of cleaned mangoes = 38
Total number of mangoes =
Sold mangoes + Spoiled mangoes + remaining mangoes (cleaned mangoes)
=>X = (X/25) + (X/5) + 38
LCM of 25 and 5 = 25
=> X = [(X×1)+(X×5)+(38×25)]/25
=>X = (X+5X+950)/25
=>X = (6X+950)/25
=>X×25 = 6X+950
=>25X = 6X+950
=>25X-6X = 950
=>19X = 950
=>X = 950/19
=>X = 50
Total mangoes = 50
Answer:-
Total number of mangoes for the given problem is 50
Check:-
Total mangoes = 50
Sold mangoes
= 50×(1/25)
=50/25
=2
Spoiled mangoes
= 50×(1/5)
=50/5
=10
Remaining mangoes
= 50-(2+10)
=50-12
=38
Verified the given relation.