one man has 52 coins and the other man takes 4. How many coins and left with first man
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52-4=48
48 coins left with first man.
Answered by
1
Simple answer!!
One man has 52 coins.
Other man took 4 coins.
So coins left with the first man is :
52 - 4 = 48
So, coins left with the first man is 48 coins.
Hope it helped!! :-)
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