Math, asked by ashifa45700, 9 months ago

One man take 100 rupee.he purchase 3products total number 100and amount 100.1glass price 3rupees,40spoon price RS 1,1plate price 5rupees . How much plate,spoon and glass purchase

Answers

Answered by nidaeamann
1

Answer:

80 spoons + 19 plates + 1 glass = 100

Step-by-step explanation:

As per the given information, the man has total 100 Rupees and he has to buy three products in such a combination that he uses all his 100 and he gets a total of 100 items among three products.

The solutiion to the problem could be sorted as;

Let us say that;

He buys 2 sets of spoon, meaning

Number of spoons = 80

Price of two set spoons = 2

He buys 19 plates;

Number of plates = 19

Price of 19 plates = 5 x 19 = 95

Then he buys 1 glass worth 3 rupees

Total items;

80 spoons + 19 plates + 1 glass = 100

Total price

2 + 95 + 3 = 100

Answered by Swarup1998
5

Given:

• Cost of a plate = Rs. 5

• Cost of a glass = Rs. 3

• Cost of 40 spoons = Rs. 1

⇒ Cost of a spoon = Rs. 1/40

Consideration:

• Number of plates = x

• Number of glasses = y

• Number of spoons = z

Now we proceed towards the solution:

For total quantity 100, x + y + z = 100

For total cost Rs. 100, 5x + 3y + z/40 = 100

We cannot solve the two equations with three variables in any direct method.

That is why, we take z = 0, 40, 80 (< 100) to get integral values of x and y.

Here z = 0 cannot be taken as spoons must be bought.

For z = 40:

We have new set of equations,

x + y = 60

5x + 3y = 99

Multiplying the 1st equation by 5, we get

5x + 5y = 300

Subtracting the second equation from it, we get

2y = 201

or, y > 201/2, which is not an integral value.

So z ≠ 40.

For z = 80

We have new set of equations:

x + y = 20 ..... (i)

5x + 3y = 98 ..... (ii)

(i) × 5 gives

5x + 5y = 100 ..... (iii)

(iii) - (ii) gives

2y = 2

or, y = 1

Then x = 19.

Thus z = 80 can be an appropriate value.

Answer:

  • Number of plates = 19
  • Number of glasses = 1
  • Number of spoons = 80

Confirmation:

So total items = 19 + 1 + 80 = 100

& total cost = Rs. (19 × 5) + (1 × 3) + (80/40)

= Rs. (95 + 3 + 2)

= Rs. 100

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