Math, asked by srisatyajiii19, 6 months ago

one merchant buy two radio set for 1000rs and one sell it 20% loss and other 20% profit. if the selling price of radio are same, then what is the cost price of each radio?​

Answers

Answered by sateesh141996
1

Answer:

Cost of one radio = 600

Another radio = 400

Step-by-step explanation:

Bought two radio sets for Rs. 1000

Let the cost price of one radio be x

Another radio be (1000 - x)

Let the selling price be SP 1, SP 2

Now

Sold one radio at 20 % loss

Therefore SP 1 = (100 - 20) *x /100

SP 1 = 80x /100

Another radio sold at 20% profit

SP 2 = (100 + 20) ( 1000 - x) / 100

SP 2 = 120( 1000- x) / 100

SP2 = (120000 - 120 x) / 100

Given that selling prices are same

Therefore

80x/ 100 = (120000 - 120x) / 100

80x + 120x = 120000

200x = 120000

x = 600

(1000 - x) = 400

Cost of one radio = 600

Another radio = 400

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