Physics, asked by garret91, 10 months ago

One meter long string can bear maximum of 0.5 kg mass. A mass of 0.05 kg is tied to one of its end and rotated in a horizontal circle, calculate the maximum number of revolution so that string does not brakes (rev/min.)

Answers

Answered by arpit04012006

1

Answer:

94.5 rev/min

Explanation:

use Fc= mw^2r

Fc= 5N

Answered by hellyjennie

0

Explanation:

hope it helps you buddy..

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