Question

one ml of hydrogen gas at NTP contains about

Answer 1

1 mol of gas=22414 ml= Avogadro's
number(6.02*10^23) of molecules

1ml=6.02*10^23/22414=2.68*10^19
molecule s

Answer 2

Answer:

One ml of hydrogen gas at NTP contains about $2.69 \times 10^{19}\end{aligned}$.

Explanation:

One liter of hydrogen at NTP weighs 0.09 g.

$\ 22400 \mathrm{ml}$ at NTP contains $6.023 \times 10^{23}$ molecule

1 ml at NTP contains

$=\frac{6.023 \times 10^{23}}{22400}$

Simplifying the above equation as

$&=0.0002688 \times 10^{23}$

$=2.69 \times 10^{19}\end{aligned}$

1 ml at NTP contains $=2.69 \times 10^{19}\end{aligned}$

Then, the number of molecules at NTP in 1 ml of an ideal gas will be

$2.69 \times 10^{19}\end{aligned}$.

Therefore, the correct answer exists $2.69 \times 10^{19}\end{aligned}$.

#SPJ3