Question

One mode of an ideal gas at N.T.P. is subjected to
adiabatic expansion, till its value me becomes four times
the initial volume. Find the work done and change in
internal energy. Given r=1.4 and R=8.31 J mol-1K-1​

Answer 1

Answer:

One mode of an ideal gas at N.T.P. is subjected to

adiabatic expansion, till its value me becomes four times

the initial volume. Find the work done and change in

internal energy. Given r=1.4 and R=8.31 J mol-1K-1

Explanation:

As it is an adiabatic process we use

T

1

V

1

γ−1

=T

2

V

2

γ−1

or T

2

=

V

2

γ−1

T

1

V

1

γ−1

=

(2)

0.4

273

=207K

Change the Internal Energy ΔU=

(γ−1)

R

(T

1

−T

2

)

=

1.4−1

8.31(273−207)

=1369.5J