One mol of N2H4 forms the compound Y by removing 10moles of electrons.If all theN atoms in the initial compound are present in compound Y What is the oxidation number of N atom in Y
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The oxidation state of N in hydrazine is -2.
1 mole of hydrazine contains 2 moles of N and loses 10 moles of electrons. Hence, 1 N atom will lose 5 electrons. Hence, its oxidation number will increase by 5.
Hence, the oxidation number of N in compound Y will be −2+5=+3.
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