Question

one mole each of hydrogen oxygen and nitrogen are mixed in a a close container of volume 10liters and temperature 27Dreeg celecegared calculate the pressure exerted by the mixture (Rinto 8.314j Molly k​

Answer 1

Answer:

240

Explanation:

pv=nrt, p=nrt/v

p=1×8×300/10

p=240

Answer 2

The pressure exerted by the mixture is 7.4 atm

Explanation:

According to the ideal gas equation:

$PV=nRT$

P = Pressure of the gas = ?

V= Volume of the gas = 10 L

T= Temperature of the gas in kelvin = $27^0C=(27+273)K=300K$

R= Gas constant = $0.0821Latm/Kmol$

n=  moles of gas= 3  

$P\times 10L=3mol\times 0.0821Latm/Kmol\times 300K$

$P=7.4atm$

Thus the pressure exerted by the mixture is 7.4 atm

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