Question

One mole of a compound contains 36 g of carbon, three g-molecule of hydrogen and three moles of oxygen atoms. What is the empirical mass of the compound?​

Answer 1

135 g

Explanation:

Given: molar mass of Carbon = 12, molar mass of H = 1

           molar mass of Oxygen = 16

number of carbon = 36 g of Carbon = 36/12 = 3 carbon

number of Hydrogen = 3/1 = 3

number of Oxygen = 3 moles of Oxygen = 3 × O₂

Empirical formula = C₃H₃O₆

Empirical mass = 3 × 12 + 3+ 16 × 6

                          = 36 + 3 + 96

                          = 135 g