Question

One mole of a gas expands with temperature T such that its volume,V=kT^2, where k is constant. If temperature of the gas changes by 60°c, then the work done by the gas

Answer 1

Explanation:

As per definition of W,

d W = P dV

d W = R T / V dV

d W = R T / KT ^ 2 / 3 ------ 1

As,  

V = KT ^ 2 / 3

By derivating,

dV = K 2 / 3 T ^ - 1/3 dT

By integration from T1 to T2 and putting the value in equation 1 :

W = 2 / 3 R  ∫ dT

W = 2 /3 R ( T2 - T1 )

W = 2 / 3 R x 60

W =40

Answer 2

Explanation:

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