One mole of a gas expands with temperature t such that its volume, v=kt2, where k is a constant. If the temperature of the gas changes by 60oc, then the work done by the gas is:
Answers
Answered by
3
As per definition of W,
d W = P dV
d W = R T / V dV
d W = R T / KT ^ 2 / 3 ------ 1
As,
V = KT ^ 2 / 3
By derivating,
dV = K 2 / 3 T ^ - 1/3 dT
By integration from T1 to T2 and putting the value in equation 1 :
W = 2 / 3 R ∫ dT
W = 2 /3 R ( T2 - T1 )
W = 2 / 3 R x 60
W = 40 R
Similar questions