Question

One mole of a gas is allowed to expand isothermally and reversibly from a volume of 1dm³to 50dm³at 273k. Calculate w,q,∆u assuming ideal behaviour

Answer 1

Answer:

W= -8880.80 J , q= 8880.80 J and ∆u= 0

Explanation:

In isothermal expansion work done W= - 2.303 nRT log(V2/V1)

which gives W = - 8880.80J

AND ∆u= 0 since the process is isothermal. SO,

AS ∆U= Q+ W

put ∆u= 0, Q= -W hence equal to 8880.80J

HOPE IT HELPS

Answer 2

Answer:

Explanation:

thanks

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