One mole of acetic acid and ethyl alcohol are heated in presence of h2so4 on equilibrium kc is 4 what amount of ethul acetate are formed
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The way this question is phrased makes me very uneasy. The given information only refers to the stoichiometry of the reaction
HOAc+EtOH→EtOAc+H2O
But it says nothing about the concentrations or quantities of the reactants prior to the reaction. (I’m assuming the concentrations of the products were both zero to start with.)
If we make the unwarranted inference that we the reaction mixture consists entirely of 1 mol of HOAc and 1 mol of EtOH and no inert solvent, then it is possible to calculate a Kc. But I want to be clear that the inference is in no way justified by the problem statement.
At the end of the reaction, we will have 2/3 mol of EtOAc, 2/3 mol of H2O, 1/3 mol of HOAc, and 1/3 mol of EtOH. They are all contained within the same volume, and since there are equal numbers of constituents on reactant and product sides, we don’t have to bother converting quantity to concentration.
Kc=[EtOAc][H2O][HOAc][EtOH]=232132=4
HOAc+EtOH→EtOAc+H2O
But it says nothing about the concentrations or quantities of the reactants prior to the reaction. (I’m assuming the concentrations of the products were both zero to start with.)
If we make the unwarranted inference that we the reaction mixture consists entirely of 1 mol of HOAc and 1 mol of EtOH and no inert solvent, then it is possible to calculate a Kc. But I want to be clear that the inference is in no way justified by the problem statement.
At the end of the reaction, we will have 2/3 mol of EtOAc, 2/3 mol of H2O, 1/3 mol of HOAc, and 1/3 mol of EtOH. They are all contained within the same volume, and since there are equal numbers of constituents on reactant and product sides, we don’t have to bother converting quantity to concentration.
Kc=[EtOAc][H2O][HOAc][EtOH]=232132=4
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