Question

One mole of AgCl is dopped with 10^-5 mole of
AICI3 then number of Ag+ ions lost from the
lattice
1) 1.8 x 10^19
2) 1.2 x 10^18
(3) 1.8 x 10^18
4) 1.2 x 10^18​

Answer 1

Answer:1st option

Explanation:

For 1 mile of AlCl3 3 miles of AgCl are removed

10^-5 moles,3×10^-5 moles are replaced i.e. 3×10^-5×6×10^23 ions of Ag+

Answer 2

Explanation:

the above answer is right