Science, asked by richardson97, 10 months ago

One mole of ammonium carbamate dissociate as
shown below at 500 K.
NH,COONH,(s) + 2NH,(9) + CO2(g) If the
pressure exerted by the released gases is 3.0 atm,
the value of K is [Standard state = 1 atm]​

Answers

Answered by satvikparida
1

One mole of ammonium carbamate dissociate as

shown below at 500 K.

NH,COONH,(s) + 2NH,(9) + CO2(g) If the

pressure exerted by the released gases is 3.0 atm,

the value of K is [Standard state = 1 atm]​One mole of ammonium carbamate dissociate as

shown below at 500 K.

NH,COONH,(s) + 2NH,(9) + CO2(g) If the

pressure exerted by the released gases is 3.0 atm,

the value of K is [Standard state = 1 atm]​One mole of ammonium carbamate dissociate as

shown below at 500 K.

NH,COONH,(s) + 2NH,(9) + CO2(g) If the

pressure exerted by the released gases is 3.0 atm,

the value of K is [Standard state = 1 atm]​One mole of ammonium carbamate dissociate as

shown below at 500 K.

NH,COONH,(s) + 2NH,(9) + CO2(g) If the

pressure exerted by the released gases is 3.0 atm,

the value of K is [Standard state = 1 atm]​One mole of ammonium carbamate dissociate as

shown below at 500 K.

NH,COONH,(s) + 2NH,(9) + CO2(g) If the

pressure exerted by the released gases is 3.0 atm,

the value of K is [Standard state = 1 atm]​One mole of ammonium carbamate dissociate as

shown below at 500 K.

NH,COONH,(s) + 2NH,(9) + CO2(g) If the

pressure exerted by the released gases is 3.0 atm,

the value of K is [Standard state = 1 atm]​One mole of ammonium carbamate dissociate as

shown below at 500 K.

NH,COONH,(s) + 2NH,(9) + CO2(g) If the

pressure exerted by the released gases is 3.0 atm,

the value of K is [Standard state = 1 atm]​One mole of ammonium carbamate dissociate as

shown below at 500 K.

NH,COONH,(s) + 2NH,(9) + CO2(g) If the

pressure exerted by the released gases is 3.0 atm,

the value of K is [Standard state = 1 atm]​

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