Chemistry, asked by arvind45961, 9 months ago

One mole of an ideal gas at 300 K is expanded
isothermally from an initial volume of 1 litre to
10 litres. The ΔE for this process is (R = 2 cal. mol⁻¹ K⁻¹)
(a) 163.7 cal (b) zero
(c) 1381.1 cal (d) 9 lit. atm

Answers

Answered by sachin2390
8

Answer:

B. Zero

Explanation:

n= 1 mole

T= 300k

V1 = 1 litres

V2 = 10 litres

For isothermal process □ E = nCv □ T

= n × Cv × 0

= 0

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