Question

One mole of an ideal gas at an initial temperature of TK dous 6R Joule of work adiabatically.
If the ratio of specific heat of this gas at constant pressure and at constant volume is 3/5 to the
final temperature of gas will be .....​

Answer 1

The final temperature of gas will be T2= (T−4)K

Explanation:

Work done in adiabatic process is given as:

T1=T

W= 6 R

γ = Cp / Cv = 5/3

T2 = ?

In an adiabatic process, W = R (T2−T1) / 1−γ

6R = R(T2−T) 1−5/3

T2 − T= 6 (−2 /3) = −4

T2= (T−4)K

Thus the final temperature of gas will be T2= (T−4)K

Also learn more

What could be the final temperature of a mixture of 100 g of water at 90°c and 600 g of water at 20°c?

https://brainly.in/question/6128442