Question

One mole of an ideal gas at temperature t1 expands according to the law

Answer 1

One mole of an ideal gas at temperature t1 expands according to the law p/v =constant.The final temperature is T2.

Suppose P/V = a(constant)

then work done = \int Pdv = \int aVdv\int aVdv\int_{v1}^{v2}avdv = (a/2)(v2square – v1square)

Now PV = nRT , n = 1,

PV = RT

P = aV

V square = RT/a

So v2 square = RT2/a

and V1 square = RT1/a

work done:  W = R(T2 – T1)/2

Answer 2

Explanation:

w=R/2(T2-T1)

this is work done