Question

One mole of an ideal gas (Cv 2.5R) is reversibly changed from 400K, 5 atm to 600K, 2 atm. Calculate the change in enthalpy, entropy and Gibbs free energy if molar entropy at 400K is 5 J/(K.mol).​

Answer 1

ΔS=2.303 n Rlog(V1V2)

=2.303×10×8.314log(10100)=191.47 JK−1

Thus ΔS=191.47JK−1

Answer 2

Answer:

(25/8)÷____=-10

25/8 ÷ (-5 /16) = -10

sᴏʟᴠɪɴɢ ʟʜs :-

25 /8 × - 16 /5

-(5 × 2)

= - 10

ʜᴇɴᴄᴇ, ᴛʜᴇ ᴀɴsᴡᴇʀ ɪs -5/16