one mole of an ideal gas expands from 5 bar to 1 bar at 298 K calculate the work done for reversible expansion?
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Answer:
Thermodynamics
Explanation:
★ Work done by Reversible Isothermal Process
[ W = - 2.303 × n × R × T × Log P1 / P2 ]
» W = -2.303 × 1 × 8.314 × 298 × Log 5 / 1
= -2.303 × 2477.5 × Log 5
= -5706 × 0.7
= - 3994 Joules
W = -3.9 K J or 39 L - atm .
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