One mole of an ideal gas expands from its initial volume of V, = V to its final volume of V, = 10 V at a constant temperature of T- 300 K. IS= 8,3 J molk, calculate the amount of heat absorbed by the gas.
Answers
Answered by
8
Q= U + W
Temp is constant so, U = 0
Q = W
W = -2.303nRT log (V2/V1)
Given, n=1 mole, T = 300K, V2= 10V, V1=V
W= -2.303*8.3*300*log(10)
W= 5734.47 J
Similar questions