Question

One mole of an ideal gas for which cv = 3/2 r is heated reversibly at a constant pressure of 1 atm from 25c to 100c. Here, h is

Answer 1

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Answer 2

Answer:

Explanation:

As we know,

️H=nCp️t

So,first ️t=100-25=75c

Then,n=1and as Cp=Cv+r

Therefore,Cp=3÷2r+r=5÷2r (r=2kcal/mol)

Hence,️H=1×5÷2×2×75

So,️H=375cal