Question

One mole of an ideal gas is heated at constant pressure from 0 to 100 degree

Answer 1

Answer:

Explanation:

internal energy = f/2 × nR∆T

for mono atomic gas f= 3

given.

n =1

and

∆T = 100-0 = 100

so

f = 3/2 ×1× 25/3 × 100

= 1250 J

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Answer 2

internal energy = f/2 × nR∆T

for mono atomic gas f= 3

Given

n =1

and

∆T = 100-0 = 100

so,

f = 3/2 ×1× 25/3 × 100

= 1250 J