Question

One mole of an ideal gas undergoes a cyclic change ABCD.From P-V diagram shown in figure,calculate the net work done on the process.

Answer 1

The work done on the process is 4 J.

Explanation:

Work done = Area under ABCD

                   = dp . dv

                   = ( 0.4 - 0.2 ) x 10^5  ( 0.3 - 1) x 10^-3

Work done = 0.2 x 0.2 x 10^2 J

Work done = 4 J

Hence the work done on the process is 4 J.

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