Question

One mole of an ideal gas undergoes an isothermal change at temperature T so that its volume Vis
doubled. R is the molar gas constant Work done by the gas during this change is
PT​

Answer 1

One mole of an ideal gas undergoes an isothermal change at temperature T so that its volume V is doubled. R is the molar gas constant.

To find : Work done by the gas during this change is ....

solution : work done by the gas in isothermal process is given by, W = nRT ln[V_f/V_i]

here initial volume , V_i = V,

final volume , V_f = 2V [ as volume is doubled ]

no of moles , n = 1

so, W = 1 × RT ln[2V/V] = RT ln2

Therefore the work done by the gas during this change is RT ln2