One mole of an ideal gas undergoes change in state (2 atm 3 litre 95 kelvin )to (4 atm 5 litre 245 kelvin ) with change in internal energy dleta u=30latm claculate the change in enthalpy of the process
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Explanation:
I don't know because I think question is wrong.
but if it is non ideal gas then ....
H2–H1=U2–U1+P2V2–P1V1=30+4×5−2×3=44L−atm.
Ans : (C)
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