Question

One mole of an ideal monatomic gas is heated at constant pressure of one atmosphere from 0 to 100 degree celsius. then the change in the internal energy is

Answer 1

internal energy = f/2 × nR∆T

for mono atomic gas f= 3

given.

n =1

and

∆T = 100-0 = 100

so

f = 3/2 ×1× 25/3 × 100

= 1250 J

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Answer 2

Hey dear,

● Answer -
∆U = 1.248 kJ

● Explaination -
# Given -
For a monoatomic gas, change in internal energy is given by -
∆U = 3/2 nR∆T
∆U = 3/2 × 1 × 8.314 × (100-0)
∆U = 1.248×10^3 J
∆U = 1.248 kJ

Therefore, change in internal energy is 1.248 kJ.


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