One mole of an ideal monoatomic gas is heated at a constant
pressure of one atmosphere from 0ºC to 100ºC. Then the
work done by the gas is
(a) 6.56 joule (b) 8.32 × 10² joule
(c) 12.48 × 10² joule (d) 20.8 × 10² joule
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Answer:
The correct answer is (c) 12.48 × 10² joule
Explanation:
For a monoatomic gas, change in internal energy is given by -
∆U = 3/2 nR∆T
∆U = 3/2 × 1 × 8.314 × (100-0)
∆U = 1.248×10^3 J
∆U = 12.48×10^2 J
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