One mole of an ideal monoatomic gas is heated at a constant pressure
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★ Internal energy = f/2 × nR∆T
for mono atomic gas f= 3
given.
n =1
and
∆T = 100-0 = 100
so
f = 3/2 ×1× 25/3 × 100
= 1250 J
for mono atomic gas f= 3
given.
n =1
and
∆T = 100-0 = 100
so
f = 3/2 ×1× 25/3 × 100
= 1250 J
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