Chemistry, asked by Aizaz93, 1 year ago

One mole of an ideal monoatomic gas y=5/3 is mixed with one mole of diatomic

Answers

Answered by deepak4963
1

For monoatomic gas;

Cv=32RT

Cp=52RT

For diatomic gas

Cv=52RT

Cp=72RT

Thus for mixture of 1 mole each

Cv=32RT+52RT2

Cp=52RT+72RT2

CpCv=3RT2RT

= 1.5

Similar questions