Question

One mole of any substance contains 6.022 x 1023 atoms/molecules. Number of molecules of H2S04 present in 100 mL of 0.02 M H2S04 solution is ​

Answer 1

Explanation:

$Moles \: of  \: H_{2}SO _{4}\\= Molarity \: of \:  H_{2} SO_{4}× Volume \: of \: solution (L) \\ </p><p>=0.02×0.1 \\ </p><p>=2× {10}^{ - 3}  moles \\ \\ </p><p></p><p></p><p>No. of H_{2} SO_{4}molecules  = \\ =2× {10}^{ - 3} ×6.022× {10}^{23} \\ =12.044× {10}^{20}  molecules</p><p>$