one mole of any substance contains 6.022x10²³ atom and molecules and number of molecules of H2so4 present in 100 ml of 0.02 M H2so4 solution is
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molarity = no. of moles/ vol. in litre
0.02 = n / 0.1
n =0.002
1mol = 6.022×10^23 molecules
:- 0.002 mol= 0.002 ×6.022×10^23
= 1.2044×102^21 molecules
0.02 = n / 0.1
n =0.002
1mol = 6.022×10^23 molecules
:- 0.002 mol= 0.002 ×6.022×10^23
= 1.2044×102^21 molecules
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