One mole of carbon-dioxide was found to occupy a volume of 1.32 litre
at 48 ° C and at a pressure of 16.4 atm. Calculate the pressure of the gas that
would have been expected to behave ideally and non-ideally.
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Answered by
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PV=nRT
=>P×1.32=1×0.08205746×321
=>P=(1×0.08205746×321K)/1.32
=>P=19.95488232atm
=>P×1.32=1×0.08205746×321
=>P=(1×0.08205746×321K)/1.32
=>P=19.95488232atm
jobanputraronil:
P1V1/T1=P2V2/T2
0.8219
Answered by
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pv=nrt
16.4×1.32=1×.821×(273+48)
21.648≠26.3541
As they are not equal they are non ideal gases....
16.4×1.32=1×.821×(273+48)
21.648≠26.3541
As they are not equal they are non ideal gases....
mark my answer best plzz!!
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