Question

one mole of carbon undergoes incomplete combustion to produce carbon monoxide. Calculate (∆H-∆U) for the formation of CO at 298K . Given R=8.314 JK^-1 mol^-1.

Answer 1

C gives Co with combine of half 02

So n=1/2

Change in enthalpy-change in internal energy=total gas moleRT

T=298k

=1/2*8.314*298k

=1238.786

Answer 2

The (∆H-∆U) for the formation of CO at 298K is 1238.786 J/mol.

Given:

R = 8.314

T = 298 K

To find:

∆H-∆U = ?

Formula to be used:

ΔH = ΔU + ΔngRT

Calculation:

The equation involved in the given reaction is as follows:

$C+\frac{1}{2}O_2\rightarrow CO$

∴ Δng = 1 - $\frac{1}{2}$ = $\frac{1}{2}$

On substituting the value of Δng in the following formula, it gives the (ΔH-ΔU) value:

ΔH = ΔU + ΔngRT

ΔH - ΔU = ΔngRT

ΔH - ΔU = $\frac{1}{2}$ × 8.314 × 298

ΔH - ΔU = 0.5 × 8.314 × 298

ΔH - ΔU = 1238.786 J/mol

Conclusion:

The value of (∆H-∆U) for the formation of CO at 298K is calculated as 1238.786 J/mol.

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