Question

One mole of Chlorine combines with certain weight of a metal giving 111g of its chloride. the same amount of metal can displace 2g of hydrogen from an acid. what is the atomic weight of the metal?

Answer 1

Answers : (1)
let metal be x
Cl2 + x = n* xCl ( n moles)
1 mole = 71g 111g
91 cl = 35.5g)
see that as it replaces 2g H = replacing 2 moles of H or 2+ charge
thus metal has 2+ charge as Ca, Mg etc or 2 moles of metal like Na, K etc.....
as Cl ha 1- charge so its two moles are used in the metal chloride as:
XCl2 type ( for Ca type metals ) or (but here it is this type - a quite logic)
2XCl type (for Na type)
so weight of chloride = 111= 2* 35.5 + x
so x=40 here see that Ca and K has this much mass bt K has 1 charge so should hv used its two moles thus finally use weight would be 80g
bt used is 40 g.
so metal is Ca and its mass is 40 g

Answer 2

Explanation:

please explain the problem