One mole of CO2 occupies 1.5 L at 27°C. Calculate the pressure exerted by the gas.
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PV = nRT
P(1.5) = 1*(0.0821)*(300)
P = (8.21)(3) / 1.5
P = (8.21)(2) = 16.42 atm
P(1.5) = 1*(0.0821)*(300)
P = (8.21)(3) / 1.5
P = (8.21)(2) = 16.42 atm
Anonymous:
here it is not...
here its 0 and 8
then yr ???
i am asking this ques because in the test i applued the value of R as 0.08 as i was not knowing the exact value....thus i got 16 atmm
in short i am asking....will my answer be considered wrong?
hmm...... good
will i get the marks...in ur opinion
not wrong but you write after answer........(something)
Ok..Thank uu very much
wlcm dear dost
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