Question

One mole of diatomic ideal gas undergoes a cyclic process ABC as shown in figure. The process BC is adiabatic.

Answer 1

Answer:

For a diatomic gas,

C

v

=

2

5

R

ΔU

BA

=nC

V

(T

B

−T

A

)=1×

2

5R

(800−400)=1000R

ΔU

AC

=ΔQ

AC

−W

AC

=nC

P

(T

A

−T

C

)−nR(T

A

−T

C

)=nC

V

(T

A

−T

C

)=1×

2

5R

(400−600)=−500R

Thus, adding up the change in internal energy in both these processes, we get change in internal energy from C to B as 500R.

As the change in internal energy is a point function we get U

BC

=−500R

Explanation:

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