one mole of ethanol is treated with one mole of ethanoic acid at 25 degree centigrade.one fourth of acid changes into ester at equilibrium. Kc for the reaction will be?
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Answer:
1/9
Explanation:
CH
3
COOH+C
2
H
5
OH⇌CH
3
COOC
2
H
5
+H
2
O
At t=0⇒1mole 1mole 0 0
At equilibrium⇒(1−
4
1
)moles(1−
4
1
)moles
4
1
moles
4
1
moles
∴Kc=
[CH
3
COOH][C
2
H
5
OH]
[CH
3
COOC
2
H
5
][H
2
O]
=
4
3
×
4
3
(
4
1
×
4
1
)
=
9
1
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