Chemistry, asked by swaroopnunnap6hvuj, 11 months ago

one mole of ethanol is treated with one mole of ethanoic acid at 25 degree centigrade.one fourth of acid changes into ester at equilibrium. Kc for the reaction will be?

Answers

Answered by s02371joshuaprince47
0

Answer:

1/9

Explanation:

CH  

3

​  

COOH+C  

2

​  

H  

5

​  

OH⇌CH  

3

​  

COOC  

2

​  

H  

5

​  

+H  

2

​  

O

At t=0⇒1mole 1mole              0                           0

At equilibrium⇒(1−  

4

1

​  

)moles(1−  

4

1

​  

)moles  

4

1

​  

moles  

4

1

​  

moles

∴Kc=  

[CH  

3

​  

COOH][C  

2

​  

H  

5

​  

OH]

[CH  

3

​  

COOC  

2

​  

H  

5

​  

][H  

2

​  

O]

​  

=  

4

3

​  

×  

4

3

​  

 

(  

4

1

​  

×  

4

1

​  

)

​  

=  

9

1

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