Question

One mole of gas is first cooled from 300k to 1500k at constant volume and then heated from 150k to 300k at constant pressure.The net heat absorbed by the gas

Answer 1

Answer:

2000...............

Answer 2

Answer:

The net heat absorbed by the gas is$150 R$

Explanation:

Given: One mole of gas is first cooled from 300k to 1500k at constant volume and then heated from 150k to 300k at constant pressure.

To find: Net heat absorbed by the gas

Solution:

Case:1

At constant volume,

Heat absorbed, $\Delta \mathrm{Q}_{1}=\mathrm{nC}_{\mathrm{v}} \Delta \mathrm{T}$

$\Rightarrow \Delta \mathrm{Q}_{1}=1 \times \mathrm{C}_{\mathrm{v}} \times(150-300)\\\=-150 \mathrm{C}_{\mathrm{v}}$

Case:2

At constant pressure,

Heat absorbed, $\Delta \mathrm{Q}_{2}=\mathrm{nC}_{\mathrm{p}} \Delta \mathrm{T}$

$\Rightarrow \Delta \mathrm{Q}_{2}=1 \times \mathrm{C}_{\mathrm{p}} \times(300-150)\\\=150 \mathrm{C}_{\mathrm{p}}$

Therefore, net heat absorbed $=\Delta \mathrm{Q}_{1}+\Delta \mathrm{Q}_{2}$

$\Rightarrow Netheatabsorbed =150\left(C_{p}-C_{v}\right)=150 R$