One mole of gas occupy 3 litre volume is expanded against a constant external pressure of one atm to a volume of 15 litre the work done by system is
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Answer:
-1.215 x 103 J
Explanation:
Work done by a system against an external pressure can be described by the following equation:
w = -Pext ∆V,
1atm = 101300 Pa , 1 L = 0.001m3
Therefore,
w = - (101300) (0.015 - 0.003)
w = - (101300) (0.012)
w = -1215.6 J = -1.215 x 103 J
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