One mole of H2O and one mole of CO are taken in 10 L vessel and heated to 725 K. At equilibrium 50% of water (by mass)
reacts with CO according to the equation,
H2O(g) + CO(g) H2(g) + CO2(g)
Calculate the equilibrium constant for the reaction
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Hyy!
Answer:-
The given reaction is:
H2O (g) + CO (g) ↔ H2 (g) + CO2 (g)
Initial Concentration: 1/10 M 1/10 M 0 0
At equilibrium 1-0.4/10 M 1-0.4/10 M 0.4/10M 0.4/10M
= 0.06M 0.06M 0.04M 0.04M
Therefore, the equilibrium constant for the reaction,
' See the above attachment '
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