one mole of H2SO4 present in solution is exactly nutralised by
1.one mole of NaOH
2.two moles of CA(OH)2
3.one mole of Ba(OH)2
4.one mole of NH3
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Answered by
0
Answer:
ans is option 3
as one mole h2so4 will furnish 2 h ions so from baoh2 1 mole u can get so
in option a only half the required moles will be furnished
in b it will be twice the required
and d will lead to some other product
Answered by
1
❤ option 3 is your answer
Explantion
when h2so4 ionises then 2h^+ + so4^2-
so to neutralise this a positive ion with charge +2 and negative ion with charge -2 is required
option 2 and 3 satisfy this condition but as we know caoh2 more soluble then baoh2 so
option 2 and 3 satisfy this condition but as we know caoh2 more soluble then baoh2 soyour answer is option 3
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